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Pythagorean theorem and special right triangles
Pythagorean theorem and special right triangles











pythagorean theorem and special right triangles

  • The side opposite the 90 º angle has the longest length and is equal to \(2x\).
  • The side opposite the 60º angle has a length equal to \(x\sqrt3\).
  • The side opposite the 30º angle is the shortest and the length of it is usually labeled as \(x\).
  • Because the angles are always in that ratio, the sides are also always in the same ratio to each other. Here’s what you need to know about 30-60-90 triangle.Ī 30-60-90 triangle is a right triangle with angle measures of 30 º, 60º, and 90º (the right angle). Because its angles and side ratios are consistent, test makers love to incorporate this triangle into problems, especially on the no-calculator portion of the SAT. The hypotenuse of this triangle is 20 c m.The 30-60-90 triangle is a special right triangle, and knowing it can save you a lot of time on standardized tests like the SAT and ACT. The hypotenuse is 10 2 2! Think: what is 2 2? It's 2, of course! And 10 × 2 = 20. What is the length of the hypotenuse in this 45-45-90 triangle? You can answer either with 13.435 f e e t, or with 9.5 2 f e e t. Here is a 45-45-90 triangle with sides measuring 9.5 f e e t. Remember, the hypotenuse is always the measure of each leg times 2! So, here the hypotenuse is 3 2 m e t e r s meters, and each leg is 3 m e t e r s. Identify the hypotenuse and legs of this 45-45-90 triangle:
  • If you know either leg's length, multiply the leg length times 2 to find the hypotenuse.
  • pythagorean theorem and special right triangles

    If you know the length of one leg, you know the length of the other leg (legs are congruent).If you know the measure of the hypotenuse, divide the hypotenuse by 2 to find the length of either leg.The length of the hypotenuse, which is the leg times 2, is key to calculating the missing sides: This method takes more time than the square method but is elegant and does not require measuring. Connect the intersections of the arcs and segments.Strike two arcs, one on the line segment and one on the perpendicular bisector.Reset the compass with the point on the intersection of the two line segments and the span of the compass set to your desired length of the triangle's leg.

    pythagorean theorem and special right triangles

    Use the straightedge to draw the perpendicular bisector by connecting the intersecting arcs.Use the compass to construct a perpendicular bisector of the line segment by scribing arcs from both endpoints above and below the line segment this will produce two intersecting arcs above and two intersecting arcs below the line segment.Open the compass to span more than half the distance of the line segment.Construct a line segment more than twice as long as the desired length of your triangle's leg.You can also construct the triangle using a straightedge and drawing compass: The diagonal becomes the hypotenuse of a right triangle. Half of a square that has been cut by a diagonal is a 45-45-90 triangle. Striking the diagonal of the square creates two congruent 45-45-90 triangles. Construct either diagonal of the square.Construct a square four equal sides to the desired length of the triangle's legs.The easiest way to construct a 45-45-90 triangle is as follows: Knowing these basic rules makes it easy to construct a 45-45-90 triangle. The main rule of 45-45-90 triangles is that it has one right angle and while the other two angles each measure 45 °.The lengths of the sides adjacent to the right triangle, the shorter sides have an equal length.Īnother rule is that the two sides of the triangle or legs of the triangle that form the right angle are congruent in length. We can plug the length of the leg into our 45-45-90 theorem formula:īoth methods produce the same result! 45-45-90 triangle rules Let's use both methods to find the unknown measure: You can also use the general form of the Pythagorean Theorem to find the length of the hypotenuse of a 45-45-90 triangle.













    Pythagorean theorem and special right triangles